Friday, March 13, 2020

Lab Book Organic Chemisty Essays

Lab Book Organic Chemisty Essays Lab Book Organic Chemisty Essay Lab Book Organic Chemisty Essay By looking at the melting points for B E and comparing them to the literature ales, it is possible to narrow the structure of both unknown compounds down from the suggest compounds in the results section (1-(3-nutritional)ethanol) or 1-(4- nutritional)ethanol) for compound B and (1-(3-anopheles)ethanol or 1-(4- anopheles)ethanol) for compound E. Mean Melting Point co 107. 0 From comparison of the two data tables it can seen that Compound E has the same melting point as compound 6, which is 1-(4-anopheles)ethanol. However for compound B the mean melting point is close to both Compound 1 and Compound 4 so IR spectra are needed to correctly determine the structure of B. By comparing the IR spectrum for Compound B it can see that it is 1- (interruption)ethanol, this is indicated by the peak at 763. CACM-1 when compared against literature values for IR Spectroscopy shows a C-H bend in the Roth position of the phenyl ring, which points to the position of ethanol being on the 4th carbon. Looking back at the yields it can be see that there has been an error in the drying process for Benzedrine resulting in a very high yield of 206%. However this is most likely to only affect the yield result, and not the chemical structure of the synthesis. Conclusion Judging by the results from the IR spectra, Melting point determination and chemical successfully synthesized. Unknown compound E was identified as compound 6, 1-(4-Anopheles) ethanol.

No comments:

Post a Comment

Note: Only a member of this blog may post a comment.